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6.5 The Area-Mach-Number Relation

Chalmers University of Technology
Department of Mechanical Engineering
Division of Fluid Dynamics

Starting point - the continuity equation (Eqn. (4.1)):

d(ρuA)=0ρuA=constd(\rho uA)=0 \Rightarrow \rho u A=const

This applies everywhere in the nozzle and therefore the sonic conditions can be used as a reference

ρuA=ρuA={u=a}=ρaA\rho uA=\rho^*u^*A^*=\left\{u^*=a^*\right\}=\rho^*a^*A^*

divide by ρuA\rho uA^* gives

ρρau=AA\frac{\rho^*}{\rho}\frac{a^*}{u}=\frac{A}{A^*}

a/u=1/Ma^*/u=1/M^* but ρ/ρ\rho^*/\rho is unknown

ρρ=ρρoρoρ\frac{\rho^*}{\rho}=\frac{\rho^*}{\rho_o}\frac{\rho_o}{\rho}

and thus

ρρoρoρ1M=AA\frac{\rho^*}{\rho_o}\frac{\rho_o}{\rho}\frac{1}{M^*}=\frac{A}{A^*}

Using the isentropic relations, we get

ρρo=1[12(γ1)]1/(γ1)\frac{\rho^*}{\rho_o}=\frac{1}{\left[\dfrac{1}{2}(\gamma-1)\right]^{1/(\gamma-1)}}
ρoρ=[1+12(γ+1)M2]1/(γ1)\frac{\rho_o}{\rho}=\left[1+\frac{1}{2}(\gamma+1)M^2\right]^{1/(\gamma-1)}

Eqns. (6.44) and (6.45) in Eqn. (6.43) gives

AA=1M[2+(γ1)M2γ+1]1/(γ1)\frac{A}{A^*}=\frac{1}{M^*}\left[\frac{2+(\gamma-1)M^2}{\gamma+1}\right]^{1/(\gamma-1)}

What remains now is to replace MM^*

M2=u2a2=u2a2a2a2=u2a2a2ao2ao2a2=M2a2ao2ao2a2{M^*}^2=\frac{u^2}{{a^*}^2}=\frac{u^2}{a^2}\frac{a^2}{{a^*}^2}=\frac{u^2}{a^2}\frac{a^2}{a_o^2}\frac{a_o^2}{{a^*}^2}=M^2\frac{a^2}{a_o^2}\frac{a_o^2}{{a^*}^2}

For a calorically perfect gas a=γRTa=\sqrt{\gamma R T}, which gives

a2ao2=TTo=[1+12(γ1)M2]1\frac{a^2}{a_o^2}=\frac{T}{T_o}=\left[1+\frac{1}{2}(\gamma-1)M^2\right]^{-1}
ao2a2=ToT=12(γ+1)\frac{a_o^2}{{a^*}^2}=\frac{T_o}{T^*}=\frac{1}{2}(\gamma+1)

Eqns. (6.48) and (6.49) in Eqn. (6.47) gives

M2=(γ+1)M22+(γ1)M2{M^*}^2=\frac{(\gamma+1)M^2}{2+(\gamma-1)M^2}

Now, rewrite Eqn. (6.46) as

(AA)2=1M2[2+(γ1)M2γ+1]2/(γ1)\left(\frac{A}{A^*}\right)^2=\frac{1}{{M^*}^2}\left[\frac{2+(\gamma-1)M^2}{\gamma+1}\right]^{2/(\gamma-1)}

and insert M2{M^*}^2 from Eqn. (6.50)

(AA)2=2+(γ1)M2(γ+1)M2[2+(γ1)M2γ+1]2/(γ1)\left(\frac{A}{A^*}\right)^2=\frac{2+(\gamma-1)M^2}{(\gamma+1)M^2}\left[\frac{2+(\gamma-1)M^2}{\gamma+1}\right]^{2/(\gamma-1)} \Rightarrow
(AA)2=1M2[2+(γ1)M2γ+1]1+2/(γ1)\left(\frac{A}{A^*}\right)^2=\frac{1}{M^2}\left[\frac{2+(\gamma-1)M^2}{\gamma+1}\right]^{1+2/(\gamma-1)} \Rightarrow
(AA)2=1M2[2+(γ1)M2γ+1](γ+1)/(γ1)\left(\frac{A}{A^*}\right)^2=\frac{1}{M^2}\left[\frac{2+(\gamma-1)M^2}{\gamma+1}\right]^{(\gamma+1)/(\gamma-1)}

which is the area-Mach-number relation.

For a nozzle flow, the area-Mach-number relation gives the Mach number, MM, at any location inside the nozzle as a function of the ratio between the local cross-section area, AA, and the throat area at choked conditions, AA^*.

M=f(AA)M=f\left(\frac{A}{A^*}\right)
Area-Mach-number relation - subsonic nozzle flow

Figure 6.4:Area-Mach-number relation - subsonic nozzle flow

Area-Mach-number relation - supersonic nozzle flow

Figure 6.5:Area-Mach-number relation - supersonic nozzle flow

Due to the assumptions made in the derivation, the area-Mach-number relation is only valid for isentropic flows of calorically perfect gases. This means that it cannot be used throughout the divergent part of a convergent-divergent nozzle in case there is a shock within the nozzle. It can, however, be used both upstream and downstream of the shock. Note that AA^* will change over the shock.